Identify the major product 'Z' in the following sequence of...

The given sequence of reactions proceeds as follows:

Step 1: $\mathrm{C_6H_5-CH_2-CH_2-Br}$ undergoes dehydrohalogenation (elimination) in the presence of alcoholic $\mathrm{KOH}$ and heat to form phenylethene (styrene).
$\mathrm{C_6H_5-CH_2-CH_2-Br} \xrightarrow[\Delta]{\text{alc. KOH}} \mathrm{C_6H_5-CH=CH_2}$ (X)

Step 2: Phenylethene undergoes electrophilic addition with $\mathrm{HBr}$. According to Markovnikov's rule, the addition proceeds via the more stable benzylic carbocation intermediate, yielding 1-bromo-1-phenylethane.
$\mathrm{C_6H_5-CH=CH_2} \xrightarrow{\mathrm{HBr}} \mathrm{C_6H_5-CH(Br)-CH_3}$ (Y)

Step 3: 1-bromo-1-phenylethane undergoes nucleophilic substitution with aqueous $\mathrm{KOH}$, replacing the bromide ion with a hydroxide ion to form 1-phenylethanol.
$\mathrm{C_6H_5-CH(Br)-CH_3} \xrightarrow[\Delta]{\text{aq. KOH}} \mathrm{C_6H_5-CH(OH)-CH_3}$ (Z)

The major product 'Z' is 1-Phenylethanol.

Answer: 1-Phenylethanol