During the elemental analysis of a newly synthesized drug molecule, 0.45 g of the sample was subjected to Liebig's combustion method. The experiment yielded 0.66 g of carbon dioxide and 0.27 g of water. What are the respective percentages of carbon and hydrogen in the drug sample?

Step-by-step solution

Mass of organic compound, W = 0.45 g Mass of CO₂ formed = 0.66 g Mass of H₂O formed = 0.27 g Percentage of carbon is given by: % C = 12 44 Mass of CO₂ Mass of compound 100 % C = 12 44 0.66 0.45 100 = 12 44 66 45 100 = 40 % Percentage of hydrogen is given by: % H = 2 18 Mass of H₂O Mass of compound 100 % H = 2 18 0.27 0.45 100 = 1 9 27 45 100 = 6.67 % Answer: 40 % and 6.67 %