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NEET 2026
Exam
NEET
Year
2026
Subject
Chemistry
Chapter
Chapter

NEET 2026 · Chemistry · Chapter

Match List I (Reagent/Test) with List II (Ion identified) based on...

Match List I (Reagent/Test) with List II (Ion identified) based on the characteristic precipitates or colors formed in
Match List I (Reagent/Test) with List II (Ion identified) based on the characteristic precipitates or colors formed in qualitative analysis:

List IList II
ADimethylglyoximeIPb2+Pb^{2+}
BPotassium chromateIICu2+Cu^{2+}
CSodium nitroprussideIIINi2+Ni^{2+}
DPotassium ferrocyanideIVS2−S^{2-}

Choose the correct answer from the options given below:

Options

  1. AA-III, B-II, C-IV, D-I
  2. BA-IV, B-I, C-III, D-II
  3. CA-III, B-I, C-IV, D-II
  4. DA-II, B-I, C-IV, D-III

Correct answer

C. A-III, B-I, C-IV, D-II

Step-by-step solution

Dimethylglyoxime reacts with Ni2+Ni^{2+} in an ammoniacal medium to form a rosy red precipitate of Ni(DMG)2Ni(DMG)_2. This corresponds to test tube A. Thus, A →\rightarrow III.

Potassium chromate reacts with Pb2+Pb^{2+} to form a yellow precipitate of lead chromate, PbCrO4PbCrO_4. This corresponds to test tube B. Thus, B →\rightarrow I.

Sodium nitroprusside reacts with sulfide ions (S2−S^{2-}) to form a purple-violet complex, [Fe(CN)5NOS]4−[Fe(CN)_5NOS]^{4-}. This corresponds to test tube C. Thus, C →\rightarrow IV.

Potassium ferrocyanide reacts with Cu2+Cu^{2+} to form a chocolate brown precipitate of copper ferrocyanide, Cu2[Fe(CN)6]Cu_2[Fe(CN)_6]. This corresponds to test tube D. Thus, D →\rightarrow II.

The correct matching is A-III, B-I, C-IV, D-II.

Answer: A-III, B-I, C-IV, D-II
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