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NEET 2026
Exam
NEET
Year
2026
Subject
Chemistry
Chapter
Chapter

NEET 2026 · Chemistry · Chapter

Consider the organic molecule shown in the figure. A chemist...

Consider the organic molecule shown in the figure. A chemist attempts to determine its nitrogen content using
Consider the organic molecule shown in the figure. A chemist attempts to determine its nitrogen content using Kjeldahl's method. Which of the following statements correctly describes the expected result?

Options

  1. AThe total nitrogen content will be accurately determined as both nitrogen atoms convert to (NH4)2SO4(NH_4)_2SO_4.
  2. BOnly the nitrogen atom of the −NO2-NO_2 group will be converted to (NH4)2SO4(NH_4)_2SO_4, leading to an underestimation.
  3. COnly the ring nitrogen atom will be converted to (NH4)2SO4(NH_4)_2SO_4, leading to an underestimation.
  4. DThe method will fail completely because neither the ring nitrogen nor the nitro nitrogen converts to (NH4)2SO4(NH_4)_2SO_4.

Correct answer

D. The method will fail completely because neither the ring nitrogen nor the nitro nitrogen converts to (NH4)2SO4(NH_4)_2SO_4.

Step-by-step solution

Kjeldahl's method is used for the quantitative estimation of nitrogen in organic compounds. In this method, the organic compound is heated with concentrated sulfuric acid, which converts the nitrogen present in the compound to ammonium sulfate, (NH4)2SO4(NH_4)_2SO_4.

However, Kjeldahl's method has specific limitations. It is not applicable to compounds containing nitrogen in:
1. Nitro groups (−NO2-NO_2)
2. Azo groups (−N=N−-N=N-)
3. Aromatic rings (e.g., pyridine, quinoline)

In these types of compounds, the nitrogen atoms are not quantitatively converted to ammonium sulfate under the standard digestion conditions.

The given molecule is 3-nitropyridine, which contains both a nitro group and a nitrogen atom within an aromatic ring (pyridine ring). Since both nitrogen atoms fall under the exceptions for Kjeldahl's method, neither will be converted to (NH4)2SO4(NH_4)_2SO_4. Therefore, the method will fail completely for this compound.

Answer: The method will fail completely because neither the ring nitrogen nor the nitro nitrogen converts to (NH4)2SO4(NH_4)_2SO_4.
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