Consider the five cyclic species (I to V) shown in the figure....

According to Huckel's rule, a species is aromatic if it is cyclic, planar, fully conjugated, and contains $(4n + 2)$ $\pi$ electrons, where $n$ is an integer ($0, 1, 2, \dots$).

(I) Naphthalene: It is a planar, fully conjugated bicyclic system with $5$ double bonds, giving $10$ $\pi$ electrons. Since $10 = 4(2) + 2$, it is aromatic.

(II) Cyclopentadienyl cation: It is a planar, fully conjugated cyclic system with $2$ double bonds, giving $4$ $\pi$ electrons. Since $4 = 4(1)$, it is antiaromatic.

(III) Pyrrole: It is a planar, fully conjugated cyclic system. The nitrogen atom contributes its lone pair to the $\pi$ system. Total $\pi$ electrons = $4$ (from double bonds) + $2$ (from lone pair) = $6$. Since $6 = 4(1) + 2$, it is aromatic.

(IV) Cyclopropenyl anion: It is a planar, fully conjugated cyclic system. The negative charge contributes $2$ electrons to the $\pi$ system. Total $\pi$ electrons = $2$ (from double bond) + $2$ (from negative charge) = $4$. Since $4 = 4(1)$, it is antiaromatic.

(V) Thiophene: It is a planar, fully conjugated cyclic system. The sulfur atom contributes one of its lone pairs to the $\pi$ system. Total $\pi$ electrons = $4$ (from double bonds) + $2$ (from lone pair) = $6$. Since $6 = 4(1) + 2$, it is aromatic.

Therefore, the aromatic species are (I), (III), and (V). There are $3$ aromatic species in total.

Answer: 3