For a He^+ ion, the distance of the electron from the nucleus in the third Bohr orbit is 238.05 pm . What will be the corresponding distance for an electron revolving in the fifth Bohr orbit of a B^ 4+ ion?

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Correct answer: B. 264.5 pm

The radius of the n -th Bohr orbit for a hydrogen-like species is given by: r_n = r_0 (n^2)/(Z) For the He^+ ion ( Z = 2 ) in the third orbit ( n = 3 ): r_ He^+ = r_0 (3^2)/(2) = 238.05 pm r_0 = (238.05 × 2)/(9) = 52.9 pm For the B^ 4+ ion ( Z = 5 ) in the fifth orbit ( n = 5 ): r_ B^ 4+ = r_0 (5^2)/(5) = 5 r_0 Substituting the value of r_0 : r_ B^ 4+ = 5 × 52.9 = 264.5 pm Answer: 264.5 pm

For a He^+ ion, the distance of the electron from the nucleus in...

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