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NEET2026ChemistryChapterActual

Based on VSEPR theory, which of the following sequences correctly represents the increasing order of bond angles for the given molecules?

Options

  1. ACH ₄ < H ₂ S < BF ₃ < BeF ₂
  2. BH ₂ S < CH ₄ < BF ₃ < BeF ₂
  3. CH ₂ S < BF ₃ < CH ₄ < BeF ₂
  4. DBeF ₂ < BF ₃ < CH ₄ < H ₂ S

Correct answer

B. H ₂ S < CH ₄ < BF ₃ < BeF ₂

Step-by-step solution

In H ₂ S , the central atom sulfur is sp^3 hybridized and has two lone pairs. Due to strong lone pair-lone pair repulsions, the bond angle decreases significantly to approximately 92^ . In CH ₄ , the central atom carbon is sp^3 hybridized with no lone pairs. The geometry is perfectly tetrahedral with a bond angle of 109.5^ . In BF ₃ , the central atom boron is sp^2 hybridized with no lone pairs. The geometry is trigonal planar with a bond angle of 120^ . In BeF ₂ , the central atom beryllium is sp hybridized with n

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