Match List I (Molecule/Ion) with List II (Shape) : List I List II A SF ₄ 1 Square planar B XeF ₄ 2 Linear C I ₃^- 3 Bent D H ₂ O 4 See-saw Choose the correct answer from the options given below:

Step-by-step solution

For SF ₄ , the central atom S has 6 valence electrons. It forms 4 bond pairs and has 1 lone pair. The hybridization is sp^3d and the shape is see-saw. For XeF ₄ , the central atom Xe has 8 valence electrons. It forms 4 bond pairs and has 2 lone pairs. The hybridization is sp^3d^2 and the shape is square planar. For I ₃^- , the central atom I has 7 valence electrons plus 1 from the negative charge, giving 8 electrons. It forms 2 bond pairs and has 3 lone pairs. The hybridization is sp^3d and the shape is linear. For