What is the total number of bonding electrons present in a nitrogen...

The total number of electrons in a nitrogen molecule ($\mathrm{N}_2$) is $14$.

The molecular orbital electronic configuration of $\mathrm{N}_2$ is:
\sigma_{1s}^{2} \sigma^{*}_{1s}^{2} \sigma_{2s}^{2} \sigma^{*}_{2s}^{2} \pi_{2p_x}^{2} \pi_{2p_y}^{2} \sigma_{2p_z}^{2}

The bonding molecular orbitals are $\sigma_{1s}$, $\sigma_{2s}$, $\pi_{2p_x}$, $\pi_{2p_y}$, and $\sigma_{2p_z}$.

Total number of bonding electrons = $2 + 2 + 2 + 2 + 2 = 10$.

Answer: $10$