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JEE MainChemistryThermodynamics (C)

2 moles of an ideal gas undergoes isothermal and reversible compression at 300 K . If the initial pressure of the gas is 1 bar and the total work done on the gas is 11488 J , the final pressure of the gas is _______ bar. (Given: 2.303 R 300 = 5744 J mol ⁻¹ )

Correct answer

10

Step-by-step solution

For an isothermal reversible process, the work done is given by: W = 2.303 nRT ( P₂ P₁ ) Since work is done on the gas during compression, W = +11488 J . Substituting the given values: 11488 = 2 (2.303 R 300) ( P₂ 1 ) 11488 = 2 5744 (P₂) 11488 = 11488 (P₂) (P₂) = 1 P₂ = 10^1 = 10 bar Answer: 10

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