An organic compound contains exactly two chlorine atoms per molecule. In a Carius estimation, 0.15 g of this compound gave 0.287 g of silver chloride. The molar mass of the organic compound (in g mol ⁻¹ ) is ______. (Given: Molar mass of Ag = 108 g mol ⁻¹ , Cl = 35.5 g mol ⁻¹ )

Step-by-step solution

First, calculate the moles of AgCl formed in the reaction. Molar mass of AgCl = 108 + 35.5 = 143.5 g mol ⁻¹ Moles of AgCl = Mass of AgCl Molar mass of AgCl = 0.287 143.5 = 0.002 mol Since one mole of AgCl contains one mole of chlorine atoms, the number of moles of chlorine atoms in the sample is 0.002 mol . It is given that each molecule of the organic compound contains exactly 2 chlorine atoms. Therefore, the moles of the organic compound will be half the moles of chlorine atoms: Moles of compound = 0.002 2 = 0.00