JEE MainChemistryChemical Bonding and Molecular Structure
An acyclic hydrocarbon X has the molecular formula C ₇ H ₁₀ . It gives a red precipitate when treated with ammoniacal cuprous chloride solution. The number of sp ^3 , sp ^2 and sp hybridised carbon atoms in X respectively are :
Options
- A1, 6, 0
- B3, 0, 4
- C2, 2, 2
- D3, 2, 2
Correct answer
D. 3, 2, 2
Step-by-step solution
First, calculate the Degree of Unsaturation (DU) for the molecular formula C ₇ H ₁₀ : DU = C - H 2 + 1 = 7 - 10 2 + 1 = 3 Since the hydrocarbon is acyclic, it must contain exactly 3 bonds. The formation of a red precipitate with ammoniacal cuprous chloride solution is a characteristic test for terminal alkynes ( - C CH ). A terminal alkyne accounts for 1 triple bond, which corresponds to 2 bonds and 2 sp hybridised carbon atoms. The remaining number of bonds is 3 - 2 = 1 . This single remaining bond must be present