In the Carius method for the estimation of halogens, 1.60 g of an organic compound gave 1.88 g of silver bromide. The percentage of bromine in the compound is ______. (Given molar masses in g mol ⁻¹ : Ag = 108 , Br = 80 )

Step-by-step solution

Molar mass of AgBr = 108 + 80 = 188 g mol ⁻¹ . Moles of AgBr formed = 1.88 188 = 0.01 mol . Since one mole of AgBr contains one mole of Br , moles of Br = 0.01 mol . Mass of bromine = 0.01 80 = 0.80 g . Percentage of bromine = Mass of bromine Mass of organic compound 100 Percentage of bromine = 0.80 1.60 100 = 50 % . Answer: 50