In an estimation of sulfur by Carius method, 0.48 g of an organic compound gave 0.699 g of barium sulfate. The percentage of sulfur in the given compound is ________. (Given: Atomic masses of Ba = 137 u , S = 32 u , O = 16 u )

Step-by-step solution

Molar mass of BaSO ₄ = 137 + 32 + 4 16 = 233 g/mol Mass of sulfur in 0.699 g of BaSO ₄ = 32 233 0.699 = 0.096 g Percentage of sulfur = Mass of sulfur Mass of organic compound 100 = 0.096 0.48 100 = 20 % Answer: 20