JEE MainChemistryGeneral Organic Chemistry
Which of the following pairs of compounds does NOT represent a pair of functional isomers?
Options
- AButan-1-amine and N-methylpropan-1-amine
- BButanamide and N-methylpropanamide
- CPropanoic acid and Methyl ethanoate
- DPentan-2-one and Pentan-3-one
Correct answer
D. Pentan-2-one and Pentan-3-one
Step-by-step solution
Functional isomers have the same molecular formula but different functional groups. (1) Butan-1-amine is a 1^ amine, while N-methylpropan-1-amine is a 2^ amine. Amines of different degrees are considered different functional groups, so they are functional isomers. (2) Butanamide is a 1^ amide, while N-methylpropanamide is a 2^ amide. Like amines, amides of different degrees are different functional groups, making them functional isomers. (3) Propanoic acid is a carboxylic acid, while methyl ethanoate is an ester. T