In a Vernier caliper, n divisions of the Vernier scale coincide exactly with (n-3) divisions of the main scale. If each main scale division measures 0.5 mm and the least count of the instrument is 0.06 mm , the value of n is:

Step-by-step solution

Let the number of Vernier scale divisions be n . Given that n Vernier scale divisions (VSD) coincide with (n-3) main scale divisions (MSD). n VSD = (n-3) MSD 1 VSD = n-3 n MSD The least count (L.C.) is given by: L.C. = 1 MSD - 1 VSD L.C. = 1 MSD - n-3 n MSD = 3 n MSD Substitute the given values ( L.C. = 0.06 mm and 1 MSD = 0.5 mm ): 0.06 = 3 n 0.5 0.06 = 1.5 n n = 1.5 0.06 = 25 Answer: 25