A Vernier calliper has a least count of 0.02 mm and each main scale division is 0.5 mm . Which of the following correctly describes the relationship between the Vernier scale divisions (VSD) and the main scale divisions (MSD)?

Step-by-step solution

The least count (LC) of a Vernier calliper is given by the difference between one main scale division and one Vernier scale division. LC = 1 MSD - 1 VSD Given that LC = 0.02 mm and 1 MSD = 0.5 mm , we can write: 0.02 mm = 0.5 mm - 1 VSD Solving for 1 VSD : 1 VSD = 0.5 mm - 0.02 mm = 0.48 mm To find the coincidence ratio, we take the ratio of the length of a VSD to an MSD: 1 VSD 1 MSD = 0.48 0.50 = 48 50 = 24 25 Rearranging this gives: 25 VSD = 24 MSD Thus, 25 Vernier scale divisions coincide with 24 main scale divi