In the Carius method for the estimation of sulphur, 2.0 g of an organic compound gave a barium sulphate precipitate. If the percentage of sulphur in the compound is 16 % , what is the mass of barium sulphate formed? (Given: Molar mass of S = 32 g mol ⁻¹ , Molar mass of BaSO ₄ = 233 g mol ⁻¹ )

Step-by-step solution

The formula for the percentage of sulphur in the Carius method is given by: % S = 32 233 Mass of BaSO ₄ Mass of organic compound 100 Rearranging to solve for the mass of BaSO ₄ : Mass of BaSO ₄ = % S 233 Mass of organic compound 32 100 Substituting the given values: Mass of BaSO ₄ = 16 233 2.0 3200 Mass of BaSO ₄ = 32 233 3200 = 233 100 = 2.33 g Answer: 2.33 g