In a Vernier caliper, 1 cm on the main scale is divided into 20 equal parts. It is given that 50 Vernier scale divisions coincide with 49 main scale divisions. When this caliper is used to measure the diameter of a

Question

Quantrex Academy · Accepted Answer

Correct answer: D. 3.124 cm

First, find the value of one main scale division (MSD).
Since

1\text{ cm}

on the main scale is divided into

20

equal parts:

1\text{ MSD} = \dfrac{1\text{ cm}}{20} = 0.05\text{ cm}

Next, determine the least count (LC) of the Vernier caliper.
We are given that

50\text{ VSD} = 49\text{ MSD}

.

1\text{ VSD} = \dfrac{49}{50}\text{ MSD}

\text{LC} = 1\text{ MSD} - 1\text{ VSD}

\text{LC} = 1\text{ MSD} - \dfrac{49}{50}\text{ MSD} = \dfrac{1}{50}\text{ MSD}

Substituting the value of

1\text{ MSD}

:

\text{LC} = \dfrac{0.05\text{ cm}}{50} = 0.001\text{ cm}

Now, calculate the total reading.
The main scale reading (MSR) is

3.1\text{ cm}

.
The Vernier scale coincidence (VSC) is

24

.

\text{Total Reading} = \text{MSR} + (\text{VSC} \times \text{LC})

\text{Total Reading} = 3.1\text{ cm} + (24 \times 0.001\text{ cm})

\text{Total Reading} = 3.1\text{ cm} + 0.024\text{ cm} = 3.124\text{ cm}

Answer:

3.124\text{ cm}

In a Vernier caliper, 1 cm on the main scale is divided into 20...

Options

Correct answer

Step-by-step solution

More from Experimental Physics