JEE MainPhysicsExperimental Physics
In a Vernier caliper, 1 cm on the main scale is divided into 20 equal parts. It is given that 50 Vernier scale divisions coincide with 49 main scale divisions. When this caliper is used to measure the diameter of a cylinder, the zero of the Vernier scale lies just after the 3.1 cm mark on the main scale, and the 24^ th division of the Vernier scale exactly coincides with a main scale division. The measured diameter o
Options
- A3.148 cm
- B3.580 cm
- C3.220 cm
- D3.124 cm
Correct answer
D. 3.124 cm
Step-by-step solution
First, find the value of one main scale division (MSD). Since 1 cm on the main scale is divided into 20 equal parts: 1 MSD = 1 cm 20 = 0.05 cm Next, determine the least count (LC) of the Vernier caliper. We are given that 50 VSD = 49 MSD . 1 VSD = 49 50 MSD LC = 1 MSD - 1 VSD LC = 1 MSD - 49 50 MSD = 1 50 MSD Substituting the value of 1 MSD : LC = 0.05 cm 50 = 0.001 cm Now, calculate the total reading. The main scale reading (MSR) is 3.1 cm . The Vernier scale coincidence (VSC) is 24 . Total Reading = MSR + ( VSC L