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JEE MainChemistryp Block Elements (Group 15, 16, 17 & 18)

Four elements of Group 15 form hydrides denoted as EH ₃ . The E-H bond lengths for these four hydrides are given as L₁ < L₂ < L₃ < L₄ . Which of the following correctly describes the properties of the hydride with the bond length L₄ among the four?

Options

  1. AIt has the lowest basicity and the highest reducing power.
  2. BIt has the highest basicity and the lowest reducing power.
  3. CIt has the lowest basicity and the lowest reducing power.
  4. DIt has the highest basicity and the highest reducing power.

Correct answer

A. It has the lowest basicity and the highest reducing power.

Step-by-step solution

The E-H bond length in Group 15 hydrides increases down the group as the atomic size of the central atom E increases. Therefore, the hydride with the longest bond length, L₄ , corresponds to the heaviest element among the four. As we move down the group, the electron density of the lone pair is dispersed over a larger volume due to the increasing size of the central atom, which leads to a decrease in Lewis basicity. Thus, the heaviest hydride has the lowest basicity. Furthermore, the increase in bond length results

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