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JEE MainChemistryChemical Bonding and Molecular Structure

Four unknown species P, Q, R, and S are described by their electronic and structural properties as follows: P : A neutral molecule with a square planar shape and an expanded octet around its central atom. Q : A cationic species with a tetrahedral geometry and a complete octet around its central atom. R : A neutral, odd-electron molecule with a bent shape and an incomplete octet around its central atom. S : A complex

Options

  1. AP = SF ₄ , Q = NH ₄⁺ , R = SO ₂ , S = [ NiCl ₄]²⁻
  2. BP = XeF ₄ , Q = NH ₄⁺ , R = NO ₂ , S = [ PtCl ₄]²⁻
  3. CP = XeF ₄ , Q = NH ₄⁺ , R = NO ₂ , S = [ Ni ( CN )₄]²⁻
  4. DP = XeF ₄ , Q = CH ₃⁺ , R = ClO ₂ , S = [ Ni ( CN )₄]²⁻

Correct answer

C. P = XeF ₄ , Q = NH ₄⁺ , R = NO ₂ , S = [ Ni ( CN )₄]²⁻

Step-by-step solution

Let us analyze the given properties for each species: P: A neutral molecule with a square planar shape and expanded octet. XeF ₄ has 4 bond pairs and 2 lone pairs ( sp^3d^2 ), making it square planar with 12 electrons around Xe. SF ₄ is see-saw shaped. Q: A cationic species with tetrahedral geometry and a complete octet. NH ₄⁺ has 4 bond pairs ( sp^3 ) and 8 electrons around N. CH ₃⁺ is trigonal planar ( sp^2 ) with 6 electrons around C. R: A neutral, odd-electron molecule with a bent shape and incomplete octet. NO

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