Consider the following list of chemical species: XeF ₂, I ₃⁻, PCl ₅, SF ₄, BrF ₃, XeF ₄, ClF ₅ Find the sum of the number of lone pairs present on the central atoms of ONLY those species from the list that possess sp ^3 d hybridization.

Step-by-step solution

First, determine the hybridization and the number of lone pairs on the central atom for each species. For XeF ₂ : Xe has 8 valence electrons. It forms 2 bonds and has 3 lone pairs. Steric number = 5 ( sp ^3 d ). For I ₃⁻ : Central I has 7 valence electrons + 1 (charge) = 8. It forms 2 bonds and has 3 lone pairs. Steric number = 5 ( sp ^3 d ). For PCl ₅ : P has 5 valence electrons. It forms 5 bonds and has 0 lone pairs. Steric number = 5 ( sp ^3 d ). For SF ₄ : S has 6 valence electrons. It forms 4 bonds and has 1 l