In the Carius method, 150 mg of a dichlorinated organic compound (containing exactly two chlorine atoms per molecule) yields 287 mg of AgCl . The molar mass of the organic compound is _______ g mol ⁻¹ . (Given : molar mass in g mol ⁻¹ of Ag : 108, Cl : 35.5 )

Step-by-step solution

Molar mass of AgCl = 108 + 35.5 = 143.5 g mol ⁻¹ . Moles of AgCl formed = 287 10⁻³ 143.5 = 2 10⁻³ mol . Since 1 mole of AgCl contains 1 mole of Cl , the moles of chlorine atoms = 2 10⁻³ mol . The organic compound contains exactly 2 chlorine atoms per molecule. Therefore, moles of the organic compound = 2 10⁻³ 2 = 10⁻³ mol . Molar mass of the compound = Mass Moles = 150 10⁻³ g 10⁻³ mol = 150 g mol ⁻¹ . Answer: 150