Consider the species NO ₃⁻ , CO ₃²⁻ and BO ₃³⁻ . Choose the correct option with respect to these three species:

Step-by-step solution

Total number of electrons in NO ₃⁻ = 7 + 3 8 + 1 = 32 Total number of electrons in CO ₃²⁻ = 6 + 3 8 + 2 = 32 Total number of electrons in BO ₃³⁻ = 5 + 3 8 + 3 = 32 All three species have 32 electrons, so they are isoelectronic. For the central atom in each species, the steric number is 1 2 (V + M - C + A) . For N in NO ₃⁻ : 1 2 (5 + 0 - 0 + 1) = 3 (sp ^2 hybridized, 0 lone pairs) For C in CO ₃²⁻ : 1 2 (4 + 0 - 0 + 2) = 3 (sp ^2 hybridized, 0 lone pairs) For B in BO ₃³⁻ : 1 2 (3 + 0 - 0 + 3) = 3 (sp ^2 hybridized, 0