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JEE MainChemistryp Block Elements (Group 15, 16, 17 & 18)

Match List I with List II. List I (Observation) List II (Reason) (A) Nitrogen does not form NCl₅ . (P) High interelectronic repulsion between non-bonding electrons. (B) Nitrogen exists as a diatomic gas ( N₂ ) at room temperature. (Q) Instability of intermediate oxidation states. (C) Catenation tendency of N is weaker than that of P. (R) Absence of vacant d-orbitals in the valence shell. (D) HNO₂ undergoes disproport

Options

  1. A(A)-(P), (B)-(S), (C)-(R), (D)-(Q)
  2. B(A)-(R), (B)-(P), (C)-(S), (D)-(Q)
  3. C(A)-(R), (B)-(Q), (C)-(P), (D)-(S)
  4. D(A)-(R), (B)-(S), (C)-(P), (D)-(Q)

Correct answer

D. (A)-(R), (B)-(S), (C)-(P), (D)-(Q)

Step-by-step solution

(A) Nitrogen cannot expand its octet to form NCl₅ because it lacks vacant d-orbitals in its valence shell. Hence, (A) matches with (R). (B) Nitrogen exists as a diatomic gas ( N₂ ) because of its unique ability to form highly effective p - p multiple bonds (triple bond) with itself, leading to discrete N₂ molecules. Hence, (B) matches with (S). (C) The catenation tendency depends on the strength of the element-element single bond. The N-N single bond is weaker than the P-P single bond due to high interelectronic re

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