JEE MainChemistryp Block Elements (Group 15, 16, 17 & 18)
Iodine reacts with an excess of fluorine to form an interhalogen compound A . Complete hydrolysis of compound A yields an oxoacid B along with hydrogen fluoride. The geometry of the anion derived from the oxoacid B is
Options
- ATetrahedral
- BOctahedral
- CSquare planar
- DTrigonal pyramidal
Correct answer
A. Tetrahedral
Step-by-step solution
Iodine reacts with excess of fluorine to form iodine heptafluoride ( IF ₇ ). I ₂ + 7 F ₂ (excess) 2 IF ₇ Complete hydrolysis of IF ₇ yields periodic acid ( HIO ₄ ) and hydrogen fluoride. IF ₇ + 4 H ₂ O HIO ₄ + 7 HF The oxoacid B is HIO ₄ , and its anion is the periodate ion, IO ₄^- . In IO ₄^- , the central iodine atom is bonded to four oxygen atoms via sigma and pi bonds, with no lone pairs on the iodine atom. The steric number is 4 , which corresponds to sp^3 hybridization. Thus, the geometry of the IO ₄^- ion is