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JEE MainChemistryp Block Elements (Group 15, 16, 17 & 18)

Iodine reacts with concentrated HNO ₃ to yield an oxyacid 'X' and a nitrogen-containing gas 'Y'. The oxidation state of the central atom in 'X' and the hybridization of the central atom in 'Y' are respectively:

Options

  1. A+7 and sp ^2
  2. B+5 and sp ^3
  3. C+5 and sp
  4. D+5 and sp ^2

Correct answer

D. +5 and sp ^2

Step-by-step solution

Concentrated nitric acid oxidizes iodine to iodic acid ( HIO ₃ ) and is itself reduced to nitrogen dioxide ( NO ₂ ). The reaction is: I ₂ + 10 HNO ₃ 2 HIO ₃ + 10 NO ₂ + 4 H ₂ O Thus, the oxyacid 'X' is HIO ₃ and the gas 'Y' is NO ₂ . In HIO ₃ , let the oxidation state of iodine be x . +1 + x + 3(-2) = 0 x = +5 In NO ₂ , the central nitrogen atom is bonded to two oxygen atoms and has one unpaired electron. The steric number is 2 (sigma bonds) + 1 (unpaired electron) = 3 . Therefore, the hybridization of nitrogen in

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