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JEE MainChemistryp Block Elements (Group 15, 16, 17 & 18)

An aqueous solution of ammonium chloride reacts with sodium nitrite to produce a diatomic gas A. Gas A reacts with hydrogen gas at 773 K in the presence of an iron catalyst to form gas B. When gas B is passed through an aqueous suspension of AgCl , the precipitate dissolves to form a water-soluble complex C. The chemical formula of the complex C is :

Options

  1. A[ Ag ( NH ₃)₄] Cl
  2. B[ Ag ( NH ₃)₂] Cl
  3. C[ Ag ( NH ₃)₂] Cl ₂
  4. D( NH ₄)₂[ AgCl ₃]

Correct answer

B. [ Ag ( NH ₃)₂] Cl

Step-by-step solution

The reaction of aqueous ammonium chloride with sodium nitrite produces dinitrogen gas ( N ₂ ). NH ₄ Cl(aq) + NaNO ₂ (aq) N ₂ (g) + 2 H ₂ O(l) + NaCl(aq) Thus, gas A is N ₂ . In the Haber process, N ₂ reacts with H ₂ at 773 K in the presence of an iron catalyst to form ammonia ( NH ₃ ). N ₂ (g) + 3 H ₂ (g) 2 NH ₃ (g) Thus, gas B is NH ₃ . When ammonia gas is passed through an aqueous suspension of silver chloride ( AgCl ), it dissolves due to the formation of the soluble diamminesilver(I) chloride complex. AgCl(s) +

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