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JEE MainChemistryChemical Bonding and Molecular Structure

Which of the following sets correctly represents an electron-deficient, an electron-precise, and an electron-rich molecule respectively?

Options

  1. ANH ₃, CH ₄, B ₂ H ₆
  2. BCH ₄, B ₂ H ₆, NH ₃
  3. CB ₂ H ₆, CH ₄, NH ₃
  4. DB ₂ H ₆, NH ₃, CH ₄

Correct answer

C. B ₂ H ₆, CH ₄, NH ₃

Step-by-step solution

Electron-deficient molecules do not have a complete octet or lack sufficient electrons for normal 2c-2e bonds. B ₂ H ₆ is a group 13 hydride and is electron-deficient. Electron-precise molecules have exactly 8 valence electrons around the central atom with no lone pairs. CH ₄ is a group 14 hydride and is electron-precise. Electron-rich molecules have a complete octet with one or more lone pairs on the central atom. NH ₃ is a group 15 hydride with one lone pair, making it electron-rich. Thus, the correct sequence is

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