The total enthalpy change for the conversion of 1 2 F ₂ (g) to F ^- (aq) is -790 kJ mol ⁻¹ . Given: Electron gain enthalpy of F(g) , _ eg H ^ = -330 kJ mol ⁻¹ Hydration enthalpy of F ^- (g) , _ hyd H ^ = -540 kJ mol ⁻¹ The bond dissociation enthalpy of F ₂ (g) is ________ kJ mol ⁻¹ . (Nearest integer)

Step-by-step solution

The conversion process involves three steps: 1 2 F ₂ (g) F(g) F ^- (g) F ^- (aq) Applying Hess's law: H = 1 2 _ dis H ^ _ F ₂ + _ eg H ^ _ F + _ hyd H ^ _ F ^- Substituting the given values: -790 = 1 2 _ dis H ^ _ F ₂ + (-330) + (-540) -790 = 1 2 _ dis H ^ _ F ₂ - 870 1 2 _ dis H ^ _ F ₂ = -790 + 870 = 80 _ dis H ^ _ F ₂ = 160 kJ mol ⁻¹ Answer: 160