In a Carius estimation of bromine, an organic compound is found to contain 80 % bromine by mass. When 0.50 g of this compound is heated with fuming nitric acid and silver nitrate, the mass of silver bromide formed is x 10⁻² g . The value of x is ______. (Given: Molar mass of Ag = 108 g mol ⁻¹ , Br = 80 g mol ⁻¹ )

Step-by-step solution

The formula for the percentage of bromine in Carius estimation is: % Br = Atomic mass of Br Molar mass of AgBr Mass of AgBr formed Mass of organic compound 100 Given data: % Br = 80 Mass of organic compound = 0.50 g Molar mass of AgBr = 108 + 80 = 188 g mol ⁻¹ Substituting the values into the formula: 80 = 80 188 Mass of AgBr 0.50 100 Simplifying the equation: 1 = 1 188 Mass of AgBr 0.50 100 Mass of AgBr = 188 0.50 100 = 0.94 g Expressing this in the required format: Mass of AgBr = 94 10⁻² g Comparing with x 10⁻² g