Consider the following chemical species: SF ₆ , XeF ₄ , ClF ₅ , [ ICl ₄]^- , PCl ₅ , BrF ₃ The total number of species having sp ^3 d ^2 hybridization for their central atom is

Step-by-step solution

The hybridization can be determined by calculating the steric number (SN) for the central atom in each species: SN = 1 2 ( Valence electrons + Monovalent atoms - Cationic charge + Anionic charge ) For SF ₆ : SN = 1 2 (6 + 6) = 6 sp ^3 d ^2 For XeF ₄ : SN = 1 2 (8 + 4) = 6 sp ^3 d ^2 For ClF ₅ : SN = 1 2 (7 + 5) = 6 sp ^3 d ^2 For [ ICl ₄]^- : SN = 1 2 (7 + 4 + 1) = 6 sp ^3 d ^2 For PCl ₅ : SN = 1 2 (5 + 5) = 5 sp ^3 d For BrF ₃ : SN = 1 2 (7 + 3) = 5 sp ^3 d The species with sp ^3 d ^2 hybridization are SF ₆ , XeF