MHT CET Medical202623 April 2026Morning ShiftChemistryAlcohols Phenols and EthersActual
Identify the product when propan-2-ol heated with Cu at 573 K.
Options
- Apropanol
- BPropene
- CPropanone
- Dpropanoic acid
Correct answer
C. Propanone
Step-by-step solution
Propan-2-ol is a secondary alcohol. When a secondary alcohol is heated with copper at 573 K, it undergoes dehydrogenation to form a ketone. CH₃-CH(OH)-CH₃ Cu, 573 K CH₃-CO-CH₃ + H₂ The product formed is propanone. Answer: Propanone