Identify the amount of Dihydrogen formed when 46\ g Na (molar mass...

Number of moles of Na = $\dfrac{46}{23} = 2$ moles.

The balanced chemical equation for the reaction of sodium with ethanol is:

$2\text{C}_2\text{H}_5\text{OH} + 2\text{Na} \rightarrow 2\text{C}_2\text{H}_5\text{ONa} + \text{H}_2$

From the stoichiometry of the reaction, $2$ moles of Na react with excess ethanol to produce $1$ mole of dihydrogen ($\text{H}_2$).

Since $2$ moles of Na are given, the amount of dihydrogen formed is $1$ mole.

Answer: $1$ mole