In the given reaction, the product "Z" is - CH_3-CH(OH)-CH_3 Cu / 573 K . oxidation Z

Correct answer: B. CH_3-CO-CH_3 The given reactant is CH_3-CH(OH)-CH_3 , which is propan-2-ol, a secondary alcohol. When vapours of a secondary alcohol are passed over heated copper at 573 K , it undergoes dehydrogenation to form a ketone. CH_3-CH(OH)-CH_3 Cu / 573 K CH_3-CO-CH_3 + H_2 Thus, the product Z is propanone (acetone), CH_3-CO-CH_3 . Answer: CH_3-CO-CH_3

MHT CET 202621 AprilMorning Shift

Exam: MHT CET
Year: 2026
Date: 21 April
Shift: Morning Shift
Subject: Chemistry
Chapter: Alcohols Phenols and Ethers

MHT CET 2026 · 21 April · Morning Shift · Chemistry · Alcohols Phenols and Ethers

In the given reaction, the product "Z" is - CH_3-CH(OH)-CH_3 Cu /...

In the given reaction, the product "Z" is -

\text{CH}_3\text{-CH(OH)-CH}_3 \xrightarrow{\large{\text{Cu / 573 K . oxidation}}} \text{Z}

Options

A $\text{CH}_3\text{-CHO}$
B $\text{CH}_3\text{-CO-CH}_3$
C $\text{CH}_3\text{-CH=CH}_2$
D $\text{CH}_3\text{-CH}_2\text{-COOH}$

Correct answer

B. $\text{CH}_3\text{-CO-CH}_3$

Step-by-step solution

The given reactant is

\text{CH}_3\text{-CH(OH)-CH}_3

, which is propan-2-ol, a secondary alcohol.

When vapours of a secondary alcohol are passed over heated copper at

573 \text{ K}

, it undergoes dehydrogenation to form a ketone.

\text{CH}_3\text{-CH(OH)-CH}_3 \xrightarrow{\text{Cu / 573 K}} \text{CH}_3\text{-CO-CH}_3 + \text{H}_2

Thus, the product Z is propanone (acetone),

\text{CH}_3\text{-CO-CH}_3

.

Answer:

\text{CH}_3\text{-CO-CH}_3

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