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MHT CET 202624 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
24 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Aldehydes and Ketones

MHT CET 2026 · 24 April · Evening Shift · Chemistry · Aldehydes and Ketones

What is the product obtained when Pent-3-enenitrile is treated with...

What is the product obtained when Pent-3-enenitrile is treated with DIBAL-H followed by acid hydrolysis?

Options

  1. ACH3-CH=CH-CH2-CHO\text{CH}_3\text{-CH=CH-CH}_2\text{-CHO}
  2. BCH3-(CH2)2-CH2-CHO\text{CH}_3\text{-(CH}_2)_2\text{-CH}_2\text{-CHO}
  3. CCH3-CH=CH-CH2-COOH\text{CH}_3\text{-CH=CH-CH}_2\text{-COOH}
  4. DCH3-(CH2)2-CH2OH\text{CH}_3\text{-(CH}_2)_2\text{-CH}_2\text{OH}

Correct answer

A. CH3-CH=CH-CH2-CHO\text{CH}_3\text{-CH=CH-CH}_2\text{-CHO}

Step-by-step solution

The structure of Pent-3-enenitrile is CH3-CH=CH-CH2-CN\text{CH}_3\text{-CH=CH-CH}_2\text{-CN}.

DIBAL-H (Diisobutylaluminium hydride) is a selective reducing agent that reduces nitriles to imines. Upon subsequent acid hydrolysis, the imine is converted to an aldehyde.

DIBAL-H does not reduce isolated carbon-carbon double bonds.

Therefore, the -CN\text{-CN} group is converted to a -CHO\text{-CHO} group, while the double bond remains intact.

The product formed is Pent-3-enal, which has the structure CH3-CH=CH-CH2-CHO\text{CH}_3\text{-CH=CH-CH}_2\text{-CHO}.

Answer: CH3-CH=CH-CH2-CHO\text{CH}_3\text{-CH=CH-CH}_2\text{-CHO}
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