The bond order of N ₂^+ ion is:

Step-by-step solution

The total number of electrons in N ₂^+ ion is 14 - 1 = 13 . The molecular orbital electronic configuration of N ₂^+ is: _ 1s ² ^ * _ 1s ² _ 2s ² ^ * _ 2s ² _ 2p_x ² _ 2p_y ² _ 2p_z ¹ Number of bonding electrons, N_b = 2 + 2 + 2 + 2 + 1 = 9 Number of antibonding electrons, N_a = 2 + 2 = 4 Bond order = 1 2 (N_b - N_a) Bond order = 1 2 (9 - 4) = 5 2 = 2.5 Answer: 2.5