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MHT CET 202624 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
24 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Coordination Compounds

MHT CET 2026 · 24 April · Evening Shift · Chemistry · Coordination Compounds

Identify the correct match from the following for coordinate...

Identify the correct match from the following for coordinate complex (column A) and respective geometry (column B)
Column A
Coordination complex
Column B
Geometry
(A). [Ni(CN)4]−2[Ni(CN)_4]^{-2}(I). Trigonal bipyramidal
(B). [Ag(NH3)2]+[Ag(NH_3)_2]^+(II). Linear
(C). [Ni(Cl)4]2−[Ni(Cl)_4]^{2-}(III). Tetrahedral
(D). [Fe(CO)5][Fe(CO)_5](IV). Square planar

Options

  1. A(A) - (I), (B) - (II), (C) - (III), (D) - (IV)
  2. B(A) - (IV), (B) - (II), (C) - (III), (D) - (I)
  3. C(A) - (I), (B) - (II), (C) - (IV), (D) - (III)
  4. D(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Correct answer

B. (A) - (IV), (B) - (II), (C) - (III), (D) - (I)

Step-by-step solution

For [Ni(CN)4]2−[\text{Ni}(\text{CN})_4]^{2-}, Ni2+\text{Ni}^{2+} has a 3d83d^8 configuration. CN−\text{CN}^- is a strong field ligand, causing pairing of electrons. The hybridization is dsp2dsp^2, resulting in a square planar geometry. Thus, (A) matches with (IV).

For [Ag(NH3)2]+[\text{Ag}(\text{NH}_3)_2]^+, Ag+\text{Ag}^+ has a 4d104d^{10} configuration. With a coordination number of 22, the hybridization is spsp, resulting in a linear geometry. Thus, (B) matches with (II).

For [Ni(Cl)4]2−[\text{Ni}(\text{Cl})_4]^{2-}, Ni2+\text{Ni}^{2+} has a 3d83d^8 configuration. Cl−\text{Cl}^- is a weak field ligand, so no pairing occurs. The hybridization is sp3sp^3, resulting in a tetrahedral geometry. Thus, (C) matches with (III).

For [Fe(CO)5][\text{Fe}(\text{CO})_5], Fe\text{Fe} is in the 00 oxidation state with a 3d64s23d^6 4s^2 configuration. CO\text{CO} is a strong field ligand, causing pairing of electrons to give a 3d83d^8 configuration. The hybridization is dsp3dsp^3, resulting in a trigonal bipyramidal geometry. Thus, (D) matches with (I).

The correct match is (A) - (IV), (B) - (II), (C) - (III), (D) - (I).

Answer: (A) - (IV), (B) - (II), (C) - (III), (D) - (I)
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