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MHT CET 202623 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
23 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

MHT CET 2026 · 23 April · Evening Shift · Chemistry · Electrochemistry

The resistivity of a solution is 25.0\ ·cm. Find its conductivity...

The resistivity of a solution is 25.0 Ω25.0\ \Omega·cm. Find its conductivity κ\kappa in (S cm^{-1}).).

Options

  1. A0.040.04 S cm^{-1}
  2. B0.070.07 S cm^{-1}
  3. C0.140.14 S cm^{-1}
  4. D0.3170.317 S cm^{-1}

Correct answer

A. 0.040.04 S cm^{-1}

Step-by-step solution

Conductivity κ\kappa is the reciprocal of resistivity ρ\rho.

κ=1ρ\kappa = \dfrac{1}{\rho}

Given ρ=25.0 Ω⋅cm\rho = 25.0\ \Omega\cdot\text{cm}.

κ=125.0=0.04 S cm−1\kappa = \dfrac{1}{25.0} = 0.04\ \text{S cm}^{-1}

Answer: 0.040.04 S cm^{-1}
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