How many Faraday electricity is required to reduce 0.25 g of Nb(V) to the metal? ( Atomic mass of Nb = 93)

Step-by-step solution

The reduction reaction of Nb(V) to Nb metal is given by: Nb⁵⁺ + 5e⁻ Nb This indicates that 5 moles of electrons (or 5 Faradays of electricity) are required to reduce 1 mole of Nb(V) to Nb metal. Number of moles of Nb in 0.25 g is: n = 0.25 93 The number of Faradays required is: Q = 5 n = 5 0.25 93 = 1.25 93 Q 0.01344 F = 1.34 10⁻² F Answer: 1.3 10⁻²