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MHT CET 202622 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
22 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Electrochemistry

MHT CET 2026 · 22 April · Evening Shift · Chemistry · Electrochemistry

0.1 M solution of an electrolyte A^+B^- placed in a conductivity...

0.10.1 M solution of an electrolyte A+B−\text{A}^+\text{B}^- placed in a conductivity cell with electrodes 44 cm apart and each with cross-section area equal to 2 cm22\ \text{cm}^2 was found to have a resistance of 200 Ω200\ \Omega. What is molar conductivity of the solution?

Options

  1. A100 Ω−1cm2100\ \Omega^{-1}\text{cm}^2
  2. B250 Ω−1cm2250\ \Omega^{-1}\text{cm}^2
  3. C0.250 Ω−1cm20.250\ \Omega^{-1}\text{cm}^2
  4. D400 Ω−1cm2400\ \Omega^{-1}\text{cm}^2

Correct answer

A. 100 Ω−1cm2100\ \Omega^{-1}\text{cm}^2

Step-by-step solution

Cell constant G∗=lAG^* = \dfrac{l}{A}

G∗=42=2 cm−1G^* = \dfrac{4}{2} = 2\ \text{cm}^{-1}

Conductivity κ=1R×G∗\kappa = \dfrac{1}{R} \times G^*

κ=1200×2=0.01 Ω−1cm−1\kappa = \dfrac{1}{200} \times 2 = 0.01\ \Omega^{-1}\text{cm}^{-1}

Molar conductivity Λm=κ×1000C\Lambda_m = \dfrac{\kappa \times 1000}{C}

Λm=0.01×10000.1=100 Ω−1cm2mol−1\Lambda_m = \dfrac{0.01 \times 1000}{0.1} = 100\ \Omega^{-1}\text{cm}^2\text{mol}^{-1}

Answer: 100 Ω−1cm2100\ \Omega^{-1}\text{cm}^2
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