MHT CET Medical202623 April 2026Morning ShiftChemistryElectrochemistryActual
Find the molar conductivity of 0.001 M AgNO ₃ solution if the conductivity of it is 1.2 10⁻⁴ ⁻¹ cm ⁻¹ .
Options
- A120 ⁻¹ cm ^2 mol ⁻¹ .
- B130 ⁻¹ cm ^2 mol ⁻¹ .
- C140 ⁻¹ cm ^2 mol ⁻¹ .
- D150 ⁻¹ cm ^2 mol ⁻¹ .
Correct answer
A. 120 ⁻¹ cm ^2 mol ⁻¹ .
Step-by-step solution
Given: Concentration, M = 0.001 M Conductivity, = 1.2 10⁻⁴ ⁻¹ cm ⁻¹ The formula for molar conductivity _m is: _m = 1000 M Substituting the given values: _m = 1.2 10⁻⁴ 1000 0.001 _m = 1.2 10⁻¹ 10⁻³ _m = 1.2 10^2 _m = 120 ⁻¹ cm ^2 mol ⁻¹