Which of the following formula of the third higher Homologue of CH ₃ -CH ₂ -COOH ?

Step-by-step solution

Homologous series members differ by a successive - CH ₂- unit. The given compound is propanoic acid: CH ₃ -CH ₂ -COOH . The first higher homologue is obtained by adding one - CH ₂- unit: CH ₃ -CH ₂ -CH ₂ -COOH . The second higher homologue is obtained by adding two - CH ₂- units: CH ₃ -CH ₂ -CH ₂ -CH ₂ -COOH . The third higher homologue is obtained by adding three - CH ₂- units: CH ₃ -CH ₂ -CH ₂ -CH ₂ -CH ₂ -COOH . Answer: CH ₃ -CH ₂ -CH ₂ -CH ₂ -CH ₂ -COOH