Identify the major product of the reaction between propene and HBr...

The reaction of propene with $HBr$ in the presence of peroxide proceeds via a free radical mechanism, known as the peroxide effect or Kharasch effect.

This leads to anti-Markovnikov addition. The peroxide initiates the reaction by generating a bromine free radical (Br^{\bullet}$) from$HBr$.<br><br>The bromine free radical adds to the terminal carbon of propene to generate a more stable secondary free radical:<br><br>$CH_3-CH=CH_2 + Br^{\bullet} \rightarrow CH_3-CH^{\bullet}-CH_2Br$<br><br>The secondary free radical then abstracts a hydrogen atom from another$HBr$molecule to form 1-bromopropane:<br><br>$CH_3-CH^{\bullet}-CH_2Br + HBr \rightarrow CH_3-CH_2-CH_2Br + Br^{\bullet}$<br><br>Thus, the major product is 1-bromopropane.<br><br>Answer: 1-Bromopropane$