An electric dipole is placed parallel to the electric field . Let 'W' be the work done in rotating the dipole by 60^ . Now, it is further rotated by 120^ , the total work done is [ 30^ = 60^ = 0.5, 0^ = 90^ = 1, ^c = -1]

Step-by-step solution

The work done in rotating an electric dipole in a uniform electric field from an initial angle ₁ to a final angle ₂ is given by W = pE( ₁ - ₂) . Initially, the dipole is parallel to the electric field, so ₁ = 0^ . The work done in rotating the dipole by 60^ is: W = pE( 0^ - 60^ ) W = pE(1 - 0.5) = 0.5 pE pE = 2W The dipole is further rotated by 120^ , making the final angle with the electric field ₂ = 60^ + 120^ = 180^ . The total work done from the initial position is: W_ total = pE( 0^ - 180^ ) W_ total = pE(1 -