A magnetizing field of 360\ A/m produces a magnetic flux density B = 0.6\ T in a ferromagnetic material. The permeability of the material in T-m/A is

Correct answer: B. (1)/(600) Given, magnetizing field H = 360\ A/m Magnetic flux density B = 0.6\ T The permeability of the material is given by the relation μ = (B)/(H) Substituting the given values, we get μ = (0.6)/(360) = (1)/(600)\ T-m/A Answer: (1)/(600)

MHT CET 202624 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 24 April
Shift: Evening Shift
Subject: Physics
Chapter: Magnetic Properties of Matter

MHT CET 2026 · 24 April · Evening Shift · Physics · Magnetic Properties of Matter

A magnetizing field of 360\ A/m produces a magnetic flux density B...

A magnetizing field of

360\ \text{A/m}

produces a magnetic flux density

B = 0.6\ \text{T}

in a ferromagnetic material. The permeability of the material in T-m/A is

Options

A $\dfrac{1}{300}$
B $\dfrac{1}{600}$
C $300$
D $600$

Correct answer

B. $\dfrac{1}{600}$

Step-by-step solution

Given, magnetizing field

H = 360\ \text{A/m}

Magnetic flux density

B = 0.6\ \text{T}

The permeability of the material is given by the relation

\mu = \dfrac{B}{H}

Substituting the given values, we get

\mu = \dfrac{0.6}{360} = \dfrac{1}{600}\ \text{T-m/A}

Answer:

\dfrac{1}{600}

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