A magnetic material has a relative permeability $(\mu_r)$ of $6001$ . If it is placed in a magnetizing field (magnetic intensity) $of H = 2000\ \text{A/m}$ , The total magnetic induction $(B)$ inside the material is nearly equal to
$\mu_0 = 4\pi \times 10^{-7}\ \text{T}\cdot\text{m/A}$

Question

A magnetic material has a relative permeability

(\mu_r)

of

6001

. If it is placed in a magnetizing field (magnetic intensity)

of H = 2000\ \text{A/m}

, The total magnetic induction

(B)

inside the material is nearly equal to

\mu_0 = 4\pi \times 10^{-7}\ \text{T}\cdot\text{m/A}

Quantrex Academy · Accepted Answer

Correct answer: C. 4.8π\ T

The total magnetic induction B inside a magnetic material is given by the formula: B = μ H = μ_0 μ_r H Given: Relative permeability, μ_r = 6001 6000 Magnetizing field, H = 2000\ A/m Permeability of free space, μ_0 = 4π × 10^ -7 \ T /A Substituting the given values into the formula: B = (4π × 10^ -7 ) × 6000 × 2000 B = 4π × 10^ -7 × 12 × 10^6 B = 48π × 10^ -1 B = 4.8π\ T Answer: 4.8π\ T

A magnetic material has a relative permeability (μ_r) of 6001 . If...

Options

Correct answer

Step-by-step solution

More from Magnetic Properties of Matter