A magnetizing field of 10^3 A/m produces a magnetic flux density 4 T in an iron rod. The relative permeability of the rod will be (permeability of free space ₀ = 4 10⁻⁷ SI units)

Step-by-step solution

Given H = 10^3 A/m and B = 4 T . The magnetic flux density is given by B = H = ₀ _r H . Substituting the given values: 4 = (4 10⁻⁷) _r 10^3 _r = 4 4 10⁻⁴ _r = 10^4 Answer: 10^4