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MHT CET Medical202624 April 2026Evening ShiftPhysicsMathematics in PhysicsActual

The error in measurement of radius of sphere is 0.2 % , then the percentage error in its volume is

Options

  1. A0.6 %
  2. B0.8 %
  3. C1.2 %
  4. D1.0 %

Correct answer

A. 0.6 %

Step-by-step solution

The volume of a sphere is given by V = 4 3 r^3 Taking relative error on both sides, we get V V = 3 r r Percentage error in volume is V V 100 = 3 ( r r 100 ) Given percentage error in radius is 0.2 % Therefore, percentage error in volume = 3 0.2 % = 0.6 % Answer: 0.6 %

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