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MHT CET 202625 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
25 April
Shift
Morning Shift
Subject
Physics
Chapter
Mathematics in Physics

MHT CET 2026 · 25 April · Morning Shift · Physics · Mathematics in Physics

The least count of voltmeter is 0.2 V, and least count of ammeter...

The least count of voltmeter is 0.2 V, and least count of ammeter is 1 mA. If the potential difference is 2 V, and the current is 10 mA, what is the percentage error in measurement of resistance?

Options

  1. A2%2\%
  2. B20%20\%
  3. C1%1\%
  4. D10%10\%

Correct answer

B. 20%20\%

Step-by-step solution

Resistance is given by Ohm's law:

R=VIR = \dfrac{V}{I}

The maximum percentage error in resistance is the sum of the percentage errors in voltage and current:

ΔRR×100=(ΔVV+ΔII)×100\dfrac{\Delta R}{R} \times 100 = \left( \dfrac{\Delta V}{V} + \dfrac{\Delta I}{I} \right) \times 100

Given values are:

V=2 VV = 2 \text{ V}, ΔV=0.2 V\Delta V = 0.2 \text{ V}

I=10 mAI = 10 \text{ mA}, ΔI=1 mA\Delta I = 1 \text{ mA}

Substituting these values:

ΔRR×100=(0.22+110)×100\dfrac{\Delta R}{R} \times 100 = \left( \dfrac{0.2}{2} + \dfrac{1}{10} \right) \times 100

ΔRR×100=(0.1+0.1)×100\dfrac{\Delta R}{R} \times 100 = (0.1 + 0.1) \times 100

ΔRR×100=0.2×100=20%\dfrac{\Delta R}{R} \times 100 = 0.2 \times 100 = 20\%

Answer: 20%20\%
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